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In the animation two containers are separated by a membrane. Initially, no particles can cross the membrane. Note that the red and the blue particles are identical (they are colored so you can keep track of them). Once the particles are evenly distributed in the left chamber, you are ready to let particles through. Try letting particles through the membrane. This animation allows about every other particle that hits the membrane to get through (equally in either direction). When there are about the same number of particles on both the left and right sides, pause the animation and count the number of red particles on each side and the number of blue particles on each side. Let the animation continue and stop it again a few seconds later when there are about the same number of particles on each side. Again, find the number of red and blue particles on each side. Restart.
The reason that the second membrane does not appear natural is the second law of thermodynamics. One version of the second law states that the entropy of an isolated system always stays the same or increases. Entropy is a measure of the number of possible arrangement of particles or a measure of the number of microstates available to a system. This is, in some sense, a measure of disorder in the system. Hence, natural systems tend towards greater disorder. In the animations the first membrane seems natural because it allows for the most disorderâ€”a random distribution of reds and blues on both sides. This is compared to the second membrane that only allows blue particles through, and thus the right side will always have only blue particles in it.
Another way to interpret the second law of thermodynamics is in terms of probability. It is possible with the first animation to get 0 red particles in the right chamber, but it is very unlikely (just like it is possible you will win the lottery, but it is very unlikely). Thus, it is possible that there is no difference between the membrane in the first and second animations, but it is highly unlikely. Consider the animation above with only six particles: four blue and two red. To keep track of the particles, some are different shades of blue and some are different shades of red (this is a model of classical, not quantum mechanical, particles because they are distinguishable). Run the animation and notice how often there are three blue particles on the right side when there are three particles on each side. What follows will allow you to calculate the probability of this happening and show that when there are three particles on each side there is a 20% chance that there will be three blue ones in the right chamber.
Considering the different arrangements of three particles on each side, note that there are four different ways to get three blues on the right and two reds and one blue on the left (list these and click here to show them). Similarly, there are the same four ways to get three blue particles in the left chamber.
There are six ways to get the light red on the left and the dark red on the right with two blues each (click here to show these). Again, there are the same six ways to have the dark red on the left and the light red on the right.
This gives a total of how many different arrangements (of three particles on each side)? Since all these states are equally likely, you have only a 20% chance of having three blues in the right chamber.
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As we add more particles, it becomes less likely to get all of one color on one side. With 40 particles, 30 blue and 10 red, there is only around a 0.02% chance that when there are 20 particles on each side, there will be 20 blue ones on the left and 10 red and 10 blue on the right. This is not impossible, but not very likely (better odds than your local lottery, where your odds might be around one in a couple of million). A more ordered state (20 blues on the right) is less likely, statistically, than a less ordered state (reds on both sides of the membrane, which is a more even mixing). Entropy is related to the number of available states that correspond to a given arrangement (mathematically, S = k_{B}lnW, where S is entropy, W is the number of equivalent arrangements or microstates, and k_{B} is the Boltzmann constant). Section 15.3 allows you to change particle arrangements and calculates the corresponding microstates, and thus, the most probable particle distribution for both classical systems (like this) and quantum-mechanical systems of bosons and fermions.