Problem 15.5

Start of definite integral = End of definite integral =

kBT = 0 kBT = 0.05 eV kBT = 0.1 eV kBT = 0.15 eV kBT = 0.2 eV kBT = 0.25 eV

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The graph shown represents the density of occupied states for electrons in a metal depending on energy. This function can be plotted for several different temperatures. What value of kBT corresponds to 7% of the electrons having energy greater than the Fermi energy?